Sure, here's a LEX program that converts the substring "abc" to "ABC" in the given input string:
```lex
%{
#include <stdio.h>
%}
%%
.*abc.* { printf("%s", yytext); } /* Match and print everything containing 'abc' */
. ; /* Ignore other characters */
%%
int main() {
yylex();
return 0;
}
```
Now, let's break down the code line by line:
1. `%{` and `%}`: These are used to enclose C code that should be included in the generated C code. In this case, it includes the standard input-output library (`<stdio.h>`).
2. `.*abc.*`: This is a regular expression pattern. It matches any sequence of characters that contains the substring "abc".
3. `{ printf("%s", yytext); }`: This is the action associated with the pattern. When the pattern is matched, the `yytext` variable contains the matched text. The action here is to print the matched text using `printf`.
4. `.`: This is a catch-all pattern that matches any character except a newline.
5. `;`: This semicolon terminates the action for a pattern.
6. `%%`: This double percentage sign separates the rules section from the C code section.
7. `int main() {`: This is the start of the `main` function where the Lex-generated code begins.
8. `yylex();`: This function call initiates the lexical analysis process.
9. `return 0;`: This returns a success status code from the program.
Now, when you run the program and input text that contains "abc", it will print out those parts of the text. For example, if you input "xyzabc123", the program will output "xyzabc". Any other characters that are not part of "abc" are ignored.
Keep in mind that this program doesn't directly replace "abc" with "ABC". Instead, it matches and prints out the portions of the input string that contain "abc". If you want to perform actual replacement, you would need to modify the action to replace "abc" with "ABC" and print the modified result.
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